flask文件夹列表前文修订版
书接上文:
https://blog.csdn.net/weixin_44517278/article/details/135228805
本文的代码和HTML模板已经修改了上文的问题,目前可以做到正常的上传,返回上层目录,下载
from flask import Flask, render_template, send_file, request, redirect, url_for
import os
app = Flask(__name__)
@app.template_filter('basename')
def basename_filter(value):
return os.path.basename(value)
@app.route('/')
def index():
files, folder_names, folder_name = getfile()
return render_template('index.html', files=files, folder_names=folder_names, folder_name=folder_name)
@app.route('/download/<file_name>')
def download_file(file_name):
file_name = os.path.normpath(file_name) # 替换windows环境下出现的双斜杠 \\ 为 /
return send_file(file_name, as_attachment=True)
@app.route('/show_folder/<folder_name>')
def show_folder(folder_name):
files, folder_names, folder_name = getfile(folder_name)
return render_template('index.html', files=files, folder_names=folder_names, folder_name=folder_name)
# 这里是返回上一级的目录
@app.route('/return_folder/<folder_name>')
def return_folder(folder_name):
refolder = folder_name
# 抓完全体的路径
full_path = os.path.join(os.getcwd(), refolder)
# 遍历指定(这里是当前)目录下的所有文件和文件夹
for root, dirs, files in os.walk(os.getcwd(), topdown=True):
# 遍历文件夹
for dir in dirs:
# 当此文件夹的完整路径等于传入文件夹的所有路径的时候,root就是这个文件夹的上级目录
if os.path.join(root, dir) == full_path:
# 用这个抓出来上级目录的相对路径,这条命令的作用就是抓相对路径,起始位置为start定义的位置
folder_name = os.path.relpath(root, start=os.getcwd())
# 两个目录相同的时候,相对路径就是 . , 当相对路径是这个,代表到根目录了,就不提供返回按钮了
if folder_name == ".":
folder_name = ""
files, folder_names, folder_name = getfile(folder_name)
return render_template('index.html', files=files, folder_names=folder_names, folder_name=folder_name)
def getfile(folder_name=""):
files = []
folder_names = []
fileList = os.listdir(os.path.join(os.getcwd(), folder_name))
for file in fileList:
file = os.path.join(folder_name, file)
file = os.path.normpath(file) # 替换windows环境下出现的双斜杠 \\ 为 /
if os.path.isfile(file):
files.append(file)
else:
folder_names.append(file)
return files, folder_names, folder_name
@app.route('/upload', methods=['POST'])
def upload_file():
# 接受HTML返回的需要下载的文件名
file = request.files['file']
# 接受HTML返回的folder_name的值(我这里folder_name是相对路径值)
folder_name = request.form['folder_name']
# 这里指定文件上传目录,实现选到那个路径下就上传文件到那个文件夹下
UPLOAD_FOLDER = folder_name
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER
# 检查是否有文件被上传
if 'file' not in request.files:
return 'No file part'
file = request.files['file']
# 如果用户没有选择文件,浏览器会发送一个空的文件名
if file.filename == '':
return 'No selected file'
# 保存文件到指定目录
file.save(os.path.join(app.config['UPLOAD_FOLDER'], file.filename))
files, folder_names, folder_name = getfile(folder_name)
return render_template('index.html', files=files, folder_names=folder_names, folder_name=folder_name)
if __name__ == '__main__':
app.run(debug=True)
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Folder Viewer</title>
</head>
<body>
<h1>文件上传下载列表</h1>
{% if folder_name == "" or folder_name %}
{% if folder_name == "" %}
<p>当前路径:</p>
{% else %}
<p>当前路径:</p>
<li><a href="{{ url_for('return_folder', folder_name=folder_name) }}">返回:{{ folder_name|basename }}</a></li>
{% endif %}
<form method="post" enctype="multipart/form-data" action="/upload">
<input type="file" name="file">
<input type="hidden" name="folder_name" value="{{ folder_name }}">
<input type="submit" value="Upload">
</form>
<ul>
<h2>文件:</h2>
{% for filename in files %}
<li><a href="{{ url_for('download_file', file_name=filename) }}" download>{{ filename|basename }}</a></li>
{% endfor %}
<h2>文件夹:</h2>
{% for foldername in folder_names %}
<li><a href="{{ url_for('show_folder', folder_name=foldername) }}">{{ foldername|basename }}</a></li>
{% endfor %}
</ul>
{% else %}
<p>No folder selected</p>
{% endif %}
</body>
</html>