通过网页api接口获取网页数据
鼠标右击检查
点击network
此时无数据,Ctrl+R刷新
找到api接口
直接使用request获取json信息,将所需要信息提取出来
贴代码👇
import os
import sys
import json
import time
import urllib
import requests
def output(url, dir_name):
request = urllib.request.Request(url=url, headers=headers)
time.sleep(5)
response = urllib.request.urlopen(request)
content = response.read().decode('utf-8')
dict_data = json.loads(content)
img_data = dict_data.get("data")
list_img = list(img_data)
for i in range(len(list_img)):
tmp_dic = list_img[i]
tmp_collectionId = tmp_dic.get("collectionId")
tmp_name = tmp_dic.get("name")
tmp_artist = tmp_dic.get("artist")
tmp_url = tmp_dic.get("imgUrl")
suffix = str(tmp_url)[0:str(tmp_url).index("?")].split('.')[-1]
print(str(tmp_collectionId) + "-" + tmp_name + "-" + tmp_artist + "." + suffix)
print(tmp_url)
res_img = requests.get(tmp_url)
with open(os.path.dirname(sys.argv[0]) + "/" + dir_name + "/" + str(
tmp_collectionId) + "-" + tmp_name + "-" + tmp_artist + "." + suffix, mode='wb') as file:
file.write(res_img.content)
headers = {
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/106.0.0.0 Safari/537.36'
}
url1 = "https://......." #目标网址
output(url1, "目标文件夹名")